众所周知, 掠夺比例与声望之间有一特定关系: 被抢者声望越高, 掠夺比例就越大, 反之亦然.
但两者之间的关系公式, 除了掠夺比例肯定在10%-60%以内, 其他的一直以来都是个谜.
连日来我找了几个朋友跟我做试验, 终于找到了
一、契机
某天, 我和一个朋友找到一只蛮不错的肥羊, 于是二人去了那人的两个分城拉了一下...
分城A的侦察报告:
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朋友的战报:
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分城B的侦察报告:
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我的战报:
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当时一直有监察对方的灯, 证实对方没上过线, 也肯定钱没有动过.
那时我朋友声望是1952, 我声望是2985. 而两个战报之间相隔只是4分钟, 三人的声望变化不会太大.
先看朋友的:
38346 / 73744 = 0.519988 (刚好没52%)
我的:
5925 / 17428 = 0.339970 (刚好没34%)
看看这个比例和我们的声望, 再运用简单的数学四式, 很容易就发现:
1952 * 0.52 ~ 2985 * 0.34
由于测试对象为同一人, 得出以下推论:
=%26gt; 掠夺方声望与掠夺比例成直线反比例
也就是说, 如果被掠夺方的声望不变, 掠夺方声望为 x, 掠夺比例为 y, 则有以下关系:
xy = a (此a为一常数)
现在欠的, 就是常数 a 还有被掠夺者的声望关系.
二、试验
试验前提:
1. 由于银币不会因时间而产出, 所以以下所有分析均以掠夺银币的比例作参考.
2. 所有试验结果都以即时的声望作标准, 战斗期间双方没造兵/完成建设/完成技术/损失部队等任何改变声望的因素
我立即找了那个朋友做试验: 我用一辆车子LB他刚筑的新城 (城里刚好有1000银币)
战报如下:
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320/1000 = 0.32
运用刚才的算式: xy = a, 其中 x = 2985, y = 0.32
得出 a = 955.2
再跟朋友的声望比较一下,发现 a 大约是他声望的一半, 得出以下假设:
掠夺方声望 * 掠夺比例 = 被掠夺方声望 / 2
换个方法写:
被掠夺方声望 / (2 * 掠夺方声望) = 掠夺比例
我们再试试把这次的数据代入:
被掠夺方声望 = 1952, 掠夺方声望 = 2985
1952 / (2 * 2985) = 0.326968
不到33%, 也就以32%来算.
接着几天, 我也找了几个不同的朋友验证假设.
首先我也找了一个声望比我低一些的朋友, 我LB他的新城 (城里刚好有1000银币):
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我的声望 = 3096, 他的声望 = 2447
2447 / (2 * 3096) = 0.395187
战报的结果是: 390 / 1000 = 0.39
=%26gt; 结果吻合 (同时证明了掠夺比例是取计算后的整数部份, 不会四舍五入)
然后这次找的是声望比我低很多的朋友, 留20000银币在家让我LB做测试:
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我的声望 = 3252, 他的声望 = 986
986 / (2 * 3252) = 0.151599
战报的结果是: 3000 / 20000 = 0.15
=%26gt; 结果吻合
这次换转, 由我一个声望比我低一点点的朋友LB我的一个新城 (当然, 城里也是刚好1000银币):
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我的声望 = 3581, 他的声望 = 3142
3581 / (2 * 3142) = 0.569859
战报的结果是: 560 / 1000 = 0.56
=%26gt; 结果吻合
经过多次测试, 假设得以证实.
掠夺公式为:
被掠夺方声望 / (2 * 掠夺方声望) = 掠夺比例
(当然, 若低于下限(10%)或超过上限(60%), 则以10%或60%来计算.)
至于如何有效运用此公式, 就看各下的脑筋了
PS. 以上测试其实早在两个月前已经完成了, 只是一直没什么时间整理及打出来. 幸好当时一早就把资料记录下来, 也抓了图...
特别鸣谢帮忙测试的几位朋友: Kelvin, 梦, OH
(要是有遗漏请别见怪...始终是两个月前的测试...)
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